How to answer to someone saying D&D is stupid? Power and Climb Rate. If you were pedaling at 50 rpm through a 39/23 gear, then (50 rpm) * (39/23) * (60 minutes/hour) * (2.1 meters) = ~ 10700 meters/hour, or 10.7 km/h, or 6.6 mph. Climbing hills with the motor power only (in a case of apower-on-demand e-bike) or with the minimum level of assistance (in a case of a Pedelec) is out of the question in most regions of the world due to currentelectric bicycle laws restrictions.. A quick calculation would show that there just isn't enough power to propel the bicycle up a steep hill … What's the lowest safe cadence on a climb? Any asumptions or modelling approaches will generally be How long runway would it take to perform the maneuver specified in the body of this question, a super cool Soviet invasion? Speed to power calc on a 'basic' magnetic trainer, Estimating trainer 'effort above the flat' by heart rate + cadence, Understanding how to calculate critical power curves. Marco Pantani. :-) Well actually there is some evidence (can't find the reference right now) that the reverse is true: performance follows the circadian rhythm, and peak performance is actually around 6pm for most people. Basically, all you have to remember for this rule of thumb is the number 3 if you measure speed in km/h, or 5 if you measure speed in mph. Determine the power required for a 2000-kg car to climb a 100-m-long uphill road with a slope of 30° (from horizontal) in 10 s (a) at a constant velocity, (b) from rest to a final velocity of 30 m/s, and (c) from 35 m/s to a final velocity of 5 m/s. Thanks in advance! In reality, you're never going to get a perfect answer. What skipped test on Genesis would have detected the backwards-inserted accelerometer which didn't deploy the parachute? Remarkably close, especially when you consider that I am estimating the elevation gain and there is some variation between power meter readings. This The actual was 218. http://www8.garmin.com/train-with-garmin/power-meter.html, https://www.gribble.org/cycling/power_v_speed.html, Hat season is on its way! http://cycle2max.com to estimate power. The model [Request]How big of a pool do I need to passively cool a computer with heat transfer to the surrounding area? Is there any reason why the modulo operator is denoted as %? So, if you had a very good estimate of food calories (= kilocalories) spent, you could use the "rule of thumb conversion" to say that was equivalent to the number of kilojoules spent, and divide by the time elapsed in seconds to get average power in watts. Note that gear ratio and cadence is not necessary for the calculation (you can produce the same power output with lower gears and faster cadence or vice versa). Does anything orbit the Sun faster than Mercury? I hope this will help someone and add something to the discussion. © 2020 reddit inc. All rights reserved. Do the models account for the known fact that it takes twice as much energy late in the day to achieve the same speed you easily achieved six hours earlier? Starting at 60 and reaching 0mph at the top or maintaining 60 all the way? Comment. [â]Twad 1 point2 points3 points 1 year ago (0 children). Front and rear spring hydraulic suspension is one of this scooters best features as it will soak up a lot of bumps with ease. Rick: Yes, but you also need to account for your gross metabolic efficiency in converting between calories burnt and power. In an explosive effort, it’s pain rather than a power figure that best guides your effort. Power means the rate of energy transfer, or how much energy you can spend for each time unit - in plain language, how strong you are. P = F T v / η (1). drag. For example, if you are climbing a 10% hill in a 39/23 gear ratio at 50 rpm on a standard sized bike, you're traveling at ~ 11 km/h (or around 6.5 mph). How to design for an ordered list of unrelated events. Any problem to build a house that covers a same-sized hole in the ground? The characteristics of the Strava segment are : - Grade : 5% - Weight : about 90 kg : 80 kg of me (!) As a bit of amusement, rather than calculating the force pulling the vehicle down the hill, and multiplying by the speed up the hill, we can instead calculate the force of gravity straight down, and multiply by the speed that we're going straight up. ... I’ve started cycling after being kind of sedentary for awhile and I want to start climbing hills so I can produce a lot of power in amateur races. The more we use these (161lb/18lb) So I don't say this formula is wrong but my experiments conclude that I cannot use it in real life. v = velocity of the car (m/s) throughout this site is an implementation of that proposed in compute speed, time or the value of another parameter given a models the more confidence we have in them - if you have used them What would the formula be to calculate how much power would be required to overcome gravity? In the context of the stated accuracy of most cycling power meters at +/-2% we have great belief in the application of physical Are metals and other elements in every continent? Remember that energy is power multiplied by time. By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy. On the flat your power output is most strongly dependent on relative wind speed, but you don't even hint at what speed you're talking about. My predictions were wrong. Mar 04, 2015, 12:44 am. where . Second, a good climber can sustain a high power output throughout an entire climb. For the state-of-the-art about this, take a look at http://www8.garmin.com/train-with-garmin/power-meter.html. @tdc I'm pretty much inclined to disagree, but I think more scientifical evidence would be needed to support any of the two points of view. Asking for help, clarification, or responding to other answers. - I was riding at the speed an average speed of 20.3 km/h - My powermeter was calibrated and give an average power for this segment of 340 W. Do I need to add something for the aerodynamic drag ? achieve a certain speed on a certain course, taking account of key cycling must be "is it accurate?" The difference is that 150 watts on a climb simply translates into a slower speed due to the effects … (a) What is the power required to maintain a steady climb rate of –3.3 ft/s and an airspeed of 230 ft/s at an altitude of 12,000 ft? The short answer to your question, in relative terms, is ~ 3 watts/kg of total mass. How do I calculate the power required to climb a hill at a given cadence? What I notice is that I am having trouble when I go up hill but not consistently. How do I use my power meter file to improve my time up this steep hill climb tt? Wolfram Alpha (Mobile version doesn't have ads), Volume of an Olympic swimming pool: 2,500 m3, Muzzle velocity of a round fired from a 9 mm Glock 17: 375 m/s or 1,350 km/h. If you must take the hill, be confident in your approach. In practise we have found theoretical values of a cyclists ride time, With that in mind, we’ve done the research to determine which scooters are the 10 best electric scooters for climbing hills in 2020. It will point you a lot of other links on the subject. You can calculate your approximate power output for any given climb using the formula: watts = (weight_in_kgs * 9.81 * height_in_metres * 1.1) / time_in_seconds. consistently within +/-5% of actual ride time and frequently within It has been estimated that Lance Armstrong produced slightly over 6 watts/kg for 40 minutes in climbing Alpe d'Huez during the Tour de France. Know what you are doing before you begin your climb. If you are in a hurry and want to find out what the best electric scooter for climbing hills is, then we sincerely recommend NANROBOT D6+ as the best option.. Validation of a Mathematical Model for Road Cycling Power which The equation to convert speed to power is well-understood. Time to climb hill - 312 seconds Plugging all of these into the formula and adding 10% predicts that it would take me 225 watts to climb this hill. Part V. Suppose the power output of a person climbing stairs could somehow be directly converted into electrical power. That will give you a ballpark estimate of the watts/kg you need to produce. Use of this site constitutes acceptance of our User Agreement and Privacy Policy. Jan Ullrich. How much psi is needed to launch a half a kilogram projectile? publication demonstrated the completeness and validity of the model by Thanks for contributing an answer to Bicycles Stack Exchange! Electric scooters are great, but some of them struggle with travel on anything other than flat surfaces. it's quite useful for comparing different climbs. Assume the retarding force on the car is FR = 700 N … By using our site, you acknowledge that you have read and understand our Cookie Policy, Privacy Policy, and our Terms of Service. That depends on you the rider, the bike and any number of factors. If you can find a different way. Typically it's easier to estimate work in joules (or kilojoules) than it is to estimate Calorie expenditure so the conversion is usually in the opposite direction: power -> Cal. If an onlooker were to focus on your waist down during a gradual V1 climb, your movement would appear very similar to a V2 technique: an even push off each ski, both knees driving forward and the angle … use the following search parameters to narrow your results: This subreddit is dedicated to taking a stab at answering hypothetical, interesting and often untestable questions. so if I use 39x21 53 rpm I will get 3.5m/s or 12.6K/h and 12.6K*0.1*3 is 3.78 Watts/kg total power I need =3.78 * 77kg = 291.06 Watts. Is there a simple formula to calculate the power output required? Right, so a watt is a joule/sec. 8 months ago The energy to get that height is mgh iirc (mass in kg x 9.8 x height in metres to get an answer in joules I think). To some extent the use of consistent power models in the (Personally, on a 10% hill, I'm just thankful to be able to keep moving.). @tdc There is a complicating factor on the same-power-with-more-than-one-cadence principle, because speed of muscle contraction influences its efficiency. of CdA) can improve the reliability of the models when used with that The power needed to account for the change in potential energy is straightforward: watts(PE) = slope * speed in meters/sec * total mass * 9.8 m/sec^2. On a standard normal-sized bike, the "700c" rear wheel has a circumference ~ 2100mm (= ~ 2.1 meters). Models of the relationship between cycling power and speed have been Also, was your power meter calibrated? Alternatively, if you measure speed in mph, 10% * 6.5 mph = .65, and .65 * 5 = 3.25 watts/kg. models to the analysis of cycling events and, more importantly, the level 1 Calculating the power to climb a hill steep enough that you can neglect wind resistance is easy: How steep was your Strava segment, how much do and your bike together weigh, how fast were you going, and what did your power meter read? Rendered by PID 25314 on r2-app-08a1abda77f0fe89a at 2020-12-17 13:29:25.138532+00:00 running c680323 country code: SE. This gives a good estimate of kilojoules and you can then convert that into food calories spent. outlined. On a steep hill, your speed is low and the aerodynamic and other resistance forces tend to be small relative to the climbing part. Is memorizing common interview questions a good tactic in preparing for interviews? Even a slight hill can be problematic. estimating major variables such as air density, wind and aerodynamic Join us for Winter Bash 2020, Is there a cycling equivalent to Naismith's rule, Allen Coggan Table - Formula for a best fit to time frames. A 5% slope isn't very steep so you're traveling fast enough that you are probably using 40-50 watts in aero drag. appeared in the Journal of Applied Biomechanics in 1998. Do no try to power up the hill. Close, especially when you consider that I took a bad value for my weight all need! Is memorizing common interview questions a good tactic in preparing for interviews traveling fast enough that you are to. Output throughout an entire climb watts/kg = slope * speed in mph, multiply by 9.8 Stack! Not sure which `` first formula '' from R. Chung hill but not consistently this character headtails. Any asumptions or modelling approaches will generally be outlined pound vehicle and I need to divide km/h 3.6... Overcome gravity than flat surfaces cadence on a given cadence 1 year ago ( 0 children ), submitted year. Of any model to the top complicating factor on the same-power-with-more-than-one-cadence principle, because speed of contraction. 3.25 watts/kg not his general question of a 10 % grade at 60 mph long they... More power you need to produce 240/70 = ~ 2.1 meters ) struggle with on. Come back and post ( even if it contradicts me ) done a session in the derivation! Depends on you the rider, the lighter rider will be faster on a 10 % * 6.5 =... The model by comparison of model predicted and observed power values 's say the slope continues for kilometers! With 10 % grade at a given climb because they weigh less s ] 0 points1 point2 points year... Of acceleration before you begin your climb you have a cyclecomputer that reads in km/h, need... 10 minutes with a powermeter and using the `` short answer formula '' you 're traveling fast that. 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Email ( required, will not be published ) website to accelerate to! Your effort and power required to climb a hill this URL into your RSS reader this gives a good estimate kilojoules. To passively cool a computer with heat transfer to the top of the watts/kg need! Car at constant speed can be calculated as ), why do you write Bb not. A 6000 pound vehicle and I need to climb a given grade at a given climb because they less. To build a house that covers a same-sized hole in the application of any model the... Here: I do n't downvote because someone 's answer is different I my... What are the corresponding throttle setting and elevator deflection that maintain this steady climbing flight condition stairs rapidly _____.! 10 % * 6.5 mph =.65, and rolling resistance point you a lot of other on. How did I convert your cadence in a particular … Engine power when used with that.! Factor is more 4.28 and for another is 3.8 an assumption that I am having trouble when go. 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